What is the radius (x+1)^2+(y-1)^2=40 ?

The radius (x+1)^2+(y-1)^2=40 is r=sqrt(40)

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radius (x+1)^2+(y-1)^2=40

radius

r = 40

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 40

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 40

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (40)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 40

And the radius is:

r = 40

What is the radius (x+1)^2+(y-1)^2=40 ?
The radius (x+1)^2+(y-1)^2=40 is r=sqrt(40)