What is the radius x^2+y^2-2x-8y-19=0(1.5) ?

The radius x^2+y^2-2x-8y-19=0(1.5) is r=6

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radius x^2+y^2-2x-8y-19=0(1.5)

radius

r = 6

Solution steps

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 \cdot 1.5

Rewrite

x^{2} + y^{2} - 2 x - 8 y - 19 = 01.5

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 6

And the radius is:

r = 6

What is the radius x^2+y^2-2x-8y-19=0(1.5) ?
The radius x^2+y^2-2x-8y-19=0(1.5) is r=6