What is the radius (x-3)^2+(y-5)^2=24 ?

The radius (x-3)^2+(y-5)^2=24 is r=sqrt(24)

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radius (x-3)^2+(y-5)^2=24

radius

r = 24

Solution steps

(x - 3)^{2} + (y - 5)^{2} = 24

Rewrite

(x - 3)^{2} + (y - 5)^{2} = 24

in the form of the standard circle equation

(x - 3)^{2} + (y - 5)^{2} = (24)^{2}

Therefore the circle properties are:

(a, b) = (3, 5), r = 24

And the radius is:

r = 24

What is the radius (x-3)^2+(y-5)^2=24 ?
The radius (x-3)^2+(y-5)^2=24 is r=sqrt(24)