What is the radius 3x^2+3y^2+6x-5y=0 ?

The radius 3x^2+3y^2+6x-5y=0 is r=(sqrt(61))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

radius 3x^2+3y^2+6x-5y=0

radius

r = \frac{61}{6}

Solution steps

3 x^{2} + 3 y^{2} + 6 x - 5 y = 0

Rewrite

3 x^{2} + 3 y^{2} + 6 x - 5 y = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - \frac{5}{6})^{2} = (\frac{61}{6})^{2}

Therefore the circle properties are:

(a, b) = (- 1, \frac{5}{6}), r = \frac{61}{6}

And the radius is:

r = \frac{61}{6}

What is the radius 3x^2+3y^2+6x-5y=0 ?
The radius 3x^2+3y^2+6x-5y=0 is r=(sqrt(61))/6