{
"query": {
"display": "$$y>-x^{2}-3x+1$$",
"symbolab_question": "CONIC#y>-x^{2}-3x+1"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(-\\frac{3}{2},\\frac{13}{4}),p=-\\frac{1}{4}"
},
"steps": {
"type": "interim",
"title": "$$y>-x^{2}-3x+1:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(-\\frac{3}{2},\\:\\frac{13}{4}\\right),\\:$$and focal length $$|p|=\\frac{1}{4}$$",
"input": "y>-x^{2}-3x+1",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(y-k\\right)=\\left(x-h\\right)^{2}\\:$$ is the standard equation for an up-down facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$y>-x^{2}-3x+1\\:$$in the standard form",
"input": "y>-x^{2}-3x+1",
"steps": [
{
"type": "interim",
"title": "Complete the square $$-x^{2}-3x+1:{\\quad}-\\left(x+\\frac{3}{2}\\right)^{2}+\\frac{13}{4}$$",
"input": "-x^{2}-3x+1",
"steps": [
{
"type": "step",
"primary": "Write $$-x^{2}-3x+1\\:$$in the form: $$x^2+2ax+a^2$$",
"secondary": [
"Factor out $$-1$$"
],
"result": "-\\left(x^{2}+3x-1\\right)"
},
{
"type": "interim",
"title": "$$2a=3{\\quad:\\quad}a=\\frac{3}{2}$$",
"input": "2a=3",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2a=3",
"result": "a=\\frac{3}{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2a}{2}=\\frac{3}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "a=\\frac{3}{2}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Add and subtract $$\\left(\\frac{3}{2}\\right)^{2}\\:$$",
"result": "-\\left(x^{2}+3x-1+\\left(\\frac{3}{2}\\right)^{2}-\\left(\\frac{3}{2}\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "$$x^2+2ax+a^2=\\left(x+a\\right)^2$$",
"secondary": [
"$$x^{2}+3x+\\left(\\frac{3}{2}\\right)^{2}=\\left(x+\\frac{3}{2}\\right)^{2}$$",
"Complete the square"
],
"result": "-\\left(\\left(x+\\frac{3}{2}\\right)^{2}-1-\\left(\\frac{3}{2}\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "-\\left(x+\\frac{3}{2}\\right)^{2}+\\frac{13}{4}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Complete Square 1Eq"
}
},
{
"type": "step",
"result": "y>-\\left(x+\\frac{3}{2}\\right)^{2}+\\frac{13}{4}"
},
{
"type": "step",
"primary": "Subtract $$\\frac{13}{4}$$ from both sides",
"result": "y-\\frac{13}{4}>-\\left(x+\\frac{3}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$-1$$",
"result": "-\\left(y-\\frac{13}{4}\\right)>\\left(x+\\frac{3}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "4\\left(-\\frac{1}{4}\\right)\\left(y-\\frac{13}{4}\\right)=\\left(x-\\left(-\\frac{3}{2}\\right)\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "4\\left(-\\frac{1}{4}\\right)\\left(y-\\frac{13}{4}\\right)=\\left(x-\\left(-\\frac{3}{2}\\right)\\right)^{2}"
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(-\\frac{3}{2},\\:\\frac{13}{4}\\right),\\:p=-\\frac{1}{4}"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{(x-(-\\frac{3}{2}))^{2}}{4(-\\frac{1}{4})}+\\frac{13}{4}",
"displayFormula": "4(-\\frac{1}{4})(y-\\frac{13}{4})=(x-(-\\frac{3}{2}))^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "DASH",
"isAsymptote": false
}
},
{
"evalFormula": "y=\\frac{7}{2}",
"displayFormula": "y=\\frac{7}{2}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(-\\frac{3}{2},\\frac{13}{4})",
"(-\\frac{3}{2},3)"
],
"pointsDecimal": [
{
"fst": -1.5,
"snd": 3.25
},
{
"fst": -1.5,
"snd": 3
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"fills": [
{
"ranges": [],
"funcIndices": [],
"funcs": [],
"xIneq": false,
"yIneq": false,
"twoVar": true,
"trueAboveLine": true,
"color": "rgba(171, 181, 235, 0.3)",
"func": "y=\\frac{(x-(-\\frac{3}{2}))^{2}}{4(-\\frac{1}{4})}+\\frac{13}{4}"
}
],
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4(-\\frac{1}{4})(y-\\frac{13}{4})>(x-(-\\frac{3}{2}))^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -4.107142857142858,
"xMax": 1.964285714285714,
"yMin": -1.214285714285714,
"yMax": 4.857142857142858
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is y>-x^2-3x+1 ?
The solution to y>-x^2-3x+1 is Parabola with (h,k)=(-3/2 , 13/4),p=-1/4