{
"query": {
"display": "$$\\left(y-3\\right)^{2}=16\\left(x+5\\right)$$",
"symbolab_question": "CONIC#(y-3)^{2}=16(x+5)"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(-5,3),p=4"
},
"steps": {
"type": "interim",
"title": "$$\\left(y-3\\right)^{2}=16\\left(x+5\\right):\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(-5,\\:3\\right),\\:$$and focal length $$|p|=4$$",
"input": "\\left(y-3\\right)^{2}=16\\left(x+5\\right)",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(x-h\\right)=\\left(y-k\\right)^{2}\\:$$ is the standard equation for a right-left facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$\\left(y-3\\right)^{2}=16\\left(x+5\\right)\\:$$in the standard form:$${\\quad}4\\cdot\\:4\\left(x-\\left(-5\\right)\\right)=\\left(y-3\\right)^{2}$$",
"input": "\\left(y-3\\right)^{2}=16\\left(x+5\\right)",
"steps": [
{
"type": "step",
"primary": "Switch sides",
"result": "16\\left(x+5\\right)=\\left(y-3\\right)^{2}"
},
{
"type": "step",
"primary": "Factor $$16$$",
"result": "16\\left(x+\\frac{80}{16}\\right)=\\left(y-3\\right)^{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "16\\left(x+5\\right)=\\left(y-3\\right)^{2}"
},
{
"type": "step",
"primary": "Factor $$4$$",
"result": "4\\cdot\\:\\frac{16}{4}\\left(x+5\\right)=\\left(y-3\\right)^{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "4\\cdot\\:4\\left(x+5\\right)=\\left(y-3\\right)^{2}"
},
{
"type": "step",
"primary": "Rewrite as",
"result": "4\\cdot\\:4\\left(x-\\left(-5\\right)\\right)=\\left(y-3\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7x7c70iKgri0FohdBA3wVDUdEyZcSg/C39X/EGw3HkF4cjlLRK1jUV206qo4+vRN7UQXyIheBU4V7QznAUubIUi9u5h1Ud7PD5KuBB69wYd9L8OVsD2aF1M5xHkeonvWlN3ELcAfoz0vqKpljUqFug0BKzNvThwZxIgCl2Yl3fvOrve3E7cDlwD8G9VYfu6du3xgpIxDNDNEp1Cfe+hNU45sJuiRkp5qUYBSxRmPWUIG4uT2jKtBBZJYZyQX0ofldKeGBIOK4zF36uK2bQJjN9Q=="
}
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(-5,\\:3\\right),\\:p=4"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\sqrt{4\\cdot 4(x-(-5))}+3",
"displayFormula": "4\\cdot 4(x-(-5))=(y-3)^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\sqrt{4\\cdot 4(x-(-5))}+3",
"displayFormula": "4\\cdot 4(x-(-5))=(y-3)^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "x=-9",
"displayFormula": "x=-9",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(-5,3)",
"(-1,3)"
],
"pointsDecimal": [
{
"fst": -5,
"snd": 3
},
{
"fst": -1,
"snd": 3
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4\\cdot 4(x-(-5))=(y-3)^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -50,
"xMax": 40,
"yMin": -42,
"yMax": 48
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form:
Therefore parabola properties are:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is (y-3)^2=16(x+5) ?
The solution to (y-3)^2=16(x+5) is Parabola with (h,k)=(-5,3),p=4