{
"query": {
"display": "$$5x+3y^{2}=0$$",
"symbolab_question": "CONIC#5x+3y^{2}=0"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(0,0),p=-\\frac{5}{12}"
},
"steps": {
"type": "interim",
"title": "$$5x+3y^{2}=0:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:$$and focal length $$|p|=\\frac{5}{12}$$",
"input": "5x+3y^{2}=0",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(x-h\\right)=\\left(y-k\\right)^{2}\\:$$ is the standard equation for a right-left facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$5x+3y^{2}=0\\:$$in the standard form:$${\\quad}4\\left(-\\frac{5}{12}\\right)\\left(x-0\\right)=\\left(y-0\\right)^{2}$$",
"input": "5x+3y^{2}=0",
"steps": [
{
"type": "step",
"primary": "Subtract $$3y^{2}$$ from both sides",
"result": "5x+3y^{2}-3y^{2}=0-3y^{2}"
},
{
"type": "step",
"primary": "Refine",
"result": "5x=-3y^{2}"
},
{
"type": "step",
"primary": "Divide both sides by $$-3$$",
"result": "\\frac{5x}{-3}=\\frac{-3y^{2}}{-3}"
},
{
"type": "step",
"primary": "Simplify",
"result": "-\\frac{5x}{3}=y^{2}"
},
{
"type": "step",
"primary": "Factor $$4$$",
"result": "4\\cdot\\:\\frac{-\\frac{5}{3}}{4}x=y^{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "4\\left(-\\frac{5}{12}\\right)x=y^{2}"
},
{
"type": "step",
"primary": "Rewrite as",
"result": "4\\left(-\\frac{5}{12}\\right)\\left(x-0\\right)=\\left(y-0\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7kXWGCo61GcOAJ7H6AkpWd9g4YQc/BH29hElCH28KEycjGsBIMn028UBVvff51AwIUo+0skB3JhOoVsRyoC4GXjh2no6HYikYL/uXZaE/9Y+RUZjadPlpTubkRAByJR5EWGSaISCMW1S3mZs3994Dl4dEeJB8NSwK2cnf2Bc1WE3bdeLci9PfzmQBgUrYJA7E6UOYgVBOOp0yPwtCb5qnM3QUgoS87LFk0WHEX4+Itv8W/3uc7VtdmRaH03Lx4dDusIjaxJ4DvjTb2fbKjbvtlQ=="
}
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:p=-\\frac{5}{12}"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\sqrt{4(-\\frac{5}{12})x}+0",
"displayFormula": "4(-\\frac{5}{12})x=y^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\sqrt{4(-\\frac{5}{12})x}+0",
"displayFormula": "4(-\\frac{5}{12})x=y^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "x=\\frac{5}{12}",
"displayFormula": "x=\\frac{5}{12}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(0,0)",
"(-\\frac{5}{12},0)"
],
"pointsDecimal": [
{
"fst": 0,
"snd": 0
},
{
"fst": -0.4166666666666667,
"snd": 0
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4(-\\frac{5}{12})(x)=y^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -4.6875,
"xMax": 4.6875,
"yMin": -4.6875,
"yMax": 4.6875
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form:
Therefore parabola properties are:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is 5x+3y^2=0 ?
The solution to 5x+3y^2=0 is Parabola with (h,k)=(0,0),p=-5/12