{
"query": {
"display": "$$-f\\left(x\\right)=4x^{2}+4x-2$$",
"symbolab_question": "CONIC#-f(x)=4x^{2}+4x-2"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(-\\frac{1}{2},3),p=-\\frac{1}{16}"
},
"steps": {
"type": "interim",
"title": "$$-y=4x^{2}+4x-2:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(-\\frac{1}{2},\\:3\\right),\\:$$and focal length $$|p|=\\frac{1}{16}$$",
"input": "-y=4x^{2}+4x-2",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(y-k\\right)=\\left(x-h\\right)^{2}\\:$$ is the standard equation for an up-down facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$-y=4x^{2}+4x-2\\:$$in the standard form",
"input": "-y=4x^{2}+4x-2",
"steps": [
{
"type": "step",
"primary": "Divide by $$-1$$",
"result": "y=-4x^{2}-4x+2"
},
{
"type": "interim",
"title": "Complete the square $$-4x^{2}-4x+2:{\\quad}-4\\left(x+\\frac{1}{2}\\right)^{2}+3$$",
"input": "-4x^{2}-4x+2",
"steps": [
{
"type": "step",
"primary": "Write $$-4x^{2}-4x+2\\:$$in the form: $$x^2+2ax+a^2$$",
"secondary": [
"Factor out $$-4$$"
],
"result": "-4\\left(x^{2}+x-\\frac{1}{2}\\right)"
},
{
"type": "interim",
"title": "$$2a=1{\\quad:\\quad}a=\\frac{1}{2}$$",
"input": "2a=1",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2a=1",
"result": "a=\\frac{1}{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2a}{2}=\\frac{1}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "a=\\frac{1}{2}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Add and subtract $$\\left(\\frac{1}{2}\\right)^{2}\\:$$",
"result": "-4\\left(x^{2}+x-\\frac{1}{2}+\\left(\\frac{1}{2}\\right)^{2}-\\left(\\frac{1}{2}\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "$$x^2+2ax+a^2=\\left(x+a\\right)^2$$",
"secondary": [
"$$x^{2}+1x+\\left(\\frac{1}{2}\\right)^{2}=\\left(x+\\frac{1}{2}\\right)^{2}$$",
"Complete the square"
],
"result": "-4\\left(\\left(x+\\frac{1}{2}\\right)^{2}-\\frac{1}{2}-\\left(\\frac{1}{2}\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "-4\\left(x+\\frac{1}{2}\\right)^{2}+3"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Complete Square 1Eq"
}
},
{
"type": "step",
"result": "y=-4\\left(x+\\frac{1}{2}\\right)^{2}+3"
},
{
"type": "step",
"primary": "Subtract $$3$$ from both sides",
"result": "y-3=-4\\left(x+\\frac{1}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$-4$$",
"result": "-\\frac{1}{4}\\left(y-3\\right)=\\left(x+\\frac{1}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "4\\left(-\\frac{1}{16}\\right)\\left(y-3\\right)=\\left(x-\\left(-\\frac{1}{2}\\right)\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "4\\left(-\\frac{1}{16}\\right)\\left(y-3\\right)=\\left(x-\\left(-\\frac{1}{2}\\right)\\right)^{2}"
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(-\\frac{1}{2},\\:3\\right),\\:p=-\\frac{1}{16}"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{(x-(-\\frac{1}{2}))^{2}}{4(-\\frac{1}{16})}+3",
"displayFormula": "4(-\\frac{1}{16})(y-3)=(x-(-\\frac{1}{2}))^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=\\frac{49}{16}",
"displayFormula": "y=\\frac{49}{16}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(-\\frac{1}{2},3)",
"(-\\frac{1}{2},\\frac{47}{16})"
],
"pointsDecimal": [
{
"fst": -0.5,
"snd": 3
},
{
"fst": -0.5,
"snd": 2.9375
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4(-\\frac{1}{16})(y-3)=(x-(-\\frac{1}{2}))^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -2.6428571428571432,
"xMax": 2,
"yMin": -0.9285714285714288,
"yMax": 3.7142857142857144
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is -f(x)=4x^2+4x-2 ?
The solution to -f(x)=4x^2+4x-2 is Parabola with (h,k)=(-1/2 ,3),p=-1/16