de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

center x^2+y^2-10x+20y+61=0

Lösung

center

x^{2} + y^{2} - 10 x + 20 y + 61 = 0

Lösung

(5, - 10)

Schritte zur Lösung

x^{2} + y^{2} - 10 x + 20 y + 61 = 0

Rewrite

x^{2} + y^{2} - 10 x + 20 y + 61 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 10))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (5, - 10), r = 8

And the center is:

(5, - 10)

Graph

Beliebte Beispiele

center (X-5)^2+(Y-6)^2=36

ce n t er (X - 5)^{2} + (Y - 6)^{2} = 36

center (x-3)^2+(y+9)^2=9^2

ce n t er (x - 3)^{2} + (y + 9)^{2} = 9^{2}

center x^2+y^2=289

ce n t er x^{2} + y^{2} = 289

center (x+1)^2+(y+2)^2=25

ce n t er (x + 1)^{2} + (y + 2)^{2} = 25

center x^2+y^2-20x+64y-371=0

ce n t er x^{2} + y^{2} - 20 x + 64 y - 371 = 0