What is the center (x+1)^2+(y+2)^2=25 ?

The center (x+1)^2+(y+2)^2=25 is (-1,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center (x+1)^2+(y+2)^2=25

center

(x + 1)^{2} + (y + 2)^{2} = 25

(- 1, - 2)

Solution steps

(x + 1)^{2} + (y + 2)^{2} = 25

Rewrite

(x + 1)^{2} + (y + 2)^{2} = 25

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 2), r = 5

And the center is:

(- 1, - 2)

x^{2} + y^{2} - 20 x + 64 y - 371 = 0

4 x^{2} + 4 y^{2} - 8 y - 5 = 0

(x - 1)^{2} + (y - 4)^{2} = 9

2 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0

(x + 2)^{2} + y^{2} = 16

What is the center (x+1)^2+(y+2)^2=25 ?
The center (x+1)^2+(y+2)^2=25 is (-1,-2)