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Beliebt Geometry >

center x^2+y^2=289

Lösung

center

x^{2} + y^{2} = 289

Lösung

(0, 0)

Schritte zur Lösung

x^{2} + y^{2} = 289

Rewrite

x^{2} + y^{2} = 289

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1 7^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 17

And the center is:

(0, 0)

Graph

Beliebte Beispiele

center (x+1)^2+(y+2)^2=25

ce n t er (x + 1)^{2} + (y + 2)^{2} = 25

center x^2+y^2-20x+64y-371=0

ce n t er x^{2} + y^{2} - 20 x + 64 y - 371 = 0

center (x-1)^2+(y+2)^2=9

ce n t er (x - 1)^{2} + (y + 2)^{2} = 9

center (x-2)^2+(y+3)^2= 16/9

ce n t er (x - 2)^{2} + (y + 3)^{2} = \frac{16}{9}

center 4x^2+4y^2+36y+5=0

ce n t er 4 x^{2} + 4 y^{2} + 36 y + 5 = 0