What is x^2+y^2+2x+16y+61=0 ?

The solution to x^2+y^2+2x+16y+61=0 is Circle with (a,b)=(-1,-8),r=2

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x^2+y^2+2x+16y+61=0

x^{2} + y^{2} + 2 x + 16 y + 61 = 0

(a, b) = (- 1, - 8), r = 2

Solution steps

x^{2} + y^{2} + 2 x + 16 y + 61 = 0

Rewrite

x^{2} + y^{2} + 2 x + 16 y + 61 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 8))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 8), r = 2

What is x^2+y^2+2x+16y+61=0 ?
The solution to x^2+y^2+2x+16y+61=0 is Circle with (a,b)=(-1,-8),r=2