Solution
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
Graph
Popular Examples
(x-1/(2(3/2)))^2+y^2=(1/(2(3/2)))^24x^2-24x+4y^2+20y=39x^2+y^2+14x-12y=-81x^2-16x+64+y^2-14x+49=0x^2-2x+y^2=15
Frequently Asked Questions (FAQ)
What is x^2+y^2+6x+16y-8=0 ?
The solution to x^2+y^2+6x+16y-8=0 is Circle with (a,b)=(-3,-8),r=9