What is x^2+y^2-x-y=8 ?

The solution to x^2+y^2-x-y=8 is Circle with (a,b)=(1/2 , 1/2),r=sqrt(17/2)

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x^2+y^2-x-y=8

x^{2} + y^{2} - x - y = 8

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{17}{2}

Solution steps

x^{2} + y^{2} - x - y = 8

Rewrite

x^{2} + y^{2} - x - y = 8

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = (\frac{17}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{17}{2}

What is x^2+y^2-x-y=8 ?
The solution to x^2+y^2-x-y=8 is Circle with (a,b)=(1/2 , 1/2),r=sqrt(17/2)