What is 3x^2+18x+3y^2-6y=18 ?

The solution to 3x^2+18x+3y^2-6y=18 is Circle with (a,b)=(-3,1),r=4

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3x^2+18x+3y^2-6y=18

3 x^{2} + 18 x + 3 y^{2} - 6 y = 18

(a, b) = (- 3, 1), r = 4

Solution steps

3 x^{2} + 18 x + 3 y^{2} - 6 y = 18

Rewrite

3 x^{2} + 18 x + 3 y^{2} - 6 y = 18

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 4

4 x + 2 y = x^{2} + y^{2}

y^{(2)} + x^{(2)} - 4 x - 5 = 0

x^{2} + y^{2} = 3 x - y

3 x^{2} + 3 y^{2} - 12 x - 24 y - 48 = 0

x^{2} + y^{2} - 8 x + 4 y - 10 = 0

What is 3x^2+18x+3y^2-6y=18 ?
The solution to 3x^2+18x+3y^2-6y=18 is Circle with (a,b)=(-3,1),r=4