What is 3x^2+3y^2-12x-24y-48=0 ?

The solution to 3x^2+3y^2-12x-24y-48=0 is Circle with (a,b)=(2,4),r=6

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3x^2+3y^2-12x-24y-48=0

3 x^{2} + 3 y^{2} - 12 x - 24 y - 48 = 0

(a, b) = (2, 4), r = 6

Solution steps

3 x^{2} + 3 y^{2} - 12 x - 24 y - 48 = 0

Rewrite

3 x^{2} + 3 y^{2} - 12 x - 24 y - 48 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (2, 4), r = 6

x^{2} + y^{2} - 8 x + 4 y - 10 = 0

x^{(2)} + y^{(2)} + 8 x - 6 y = 6

yy = 9 x - x^{2}

3 x^{2} - 12 x + 3 y^{2} = 2

3 x^{2} + 3 y^{2} - 15 x - 21 y = 110

What is 3x^2+3y^2-12x-24y-48=0 ?
The solution to 3x^2+3y^2-12x-24y-48=0 is Circle with (a,b)=(2,4),r=6