What is 8x^2+8y^2=32 ?

The solution to 8x^2+8y^2=32 is Circle with (a,b)=(0,0),r=2

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8x^2+8y^2=32

8 x^{2} + 8 y^{2} = 32

(a, b) = (0, 0), r = 2

Solution steps

8 x^{2} + 8 y^{2} = 32

Rewrite

8 x^{2} + 8 y^{2} = 32

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

(2 x^{2} + 7 x) + (2 y^{2} + 4 y) = 6

(x - 1)^{2} + (y + 5)^{2} = 4^{2}

(Y - 1)^{2} + (X + 5)^{2} = 1

(x + 2)^{2} + (y - 1)^{2} = 2^{2}

0 + y^{2} + z^{2} = 1

What is 8x^2+8y^2=32 ?
The solution to 8x^2+8y^2=32 is Circle with (a,b)=(0,0),r=2