What is y^2+x^2-18x+12y+101=0 ?

The solution to y^2+x^2-18x+12y+101=0 is Circle with (a,b)=(9,-6),r=4

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y^2+x^2-18x+12y+101=0

y^{2} + x^{2} - 18 x + 12 y + 101 = 0

(a, b) = (9, - 6), r = 4

Solution steps

y^{2} + x^{2} - 18 x + 12 y + 101 = 0

Rewrite

y^{2} + x^{2} - 18 x + 12 y + 101 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 6))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (9, - 6), r = 4

What is y^2+x^2-18x+12y+101=0 ?
The solution to y^2+x^2-18x+12y+101=0 is Circle with (a,b)=(9,-6),r=4