What is x^2+2x+y^2-2y-45=0 ?

The solution to x^2+2x+y^2-2y-45=0 is Circle with (a,b)=(-1,1),r=sqrt(47)

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x^2+2x+y^2-2y-45=0

x^{2} + 2 x + y^{2} - 2 y - 45 = 0

(a, b) = (- 1, 1), r = 47

Solution steps

x^{2} + 2 x + y^{2} - 2 y - 45 = 0

Rewrite

x^{2} + 2 x + y^{2} - 2 y - 45 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (47)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 47

4 - (y - 4)^{2} = (x^{2} + 6 x + 9)

z^{2} + y^{2} = 9^{2}

x^{2} - 12 x + y^{2} - 2 y - 12 = 0

3 x^{2} + 3 y^{2} - 12 x - 48 y = 0

(x - \frac{3}{5})^{2} + (y - \frac{1}{3})^{2} = 10^{2}

What is x^2+2x+y^2-2y-45=0 ?
The solution to x^2+2x+y^2-2y-45=0 is Circle with (a,b)=(-1,1),r=sqrt(47)