What is x^2+(y+4)^2= 1/9 ?

The solution to x^2+(y+4)^2= 1/9 is Circle with (a,b)=(0,-4),r= 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+(y+4)^2= 1/9

x^{2} + (y + 4)^{2} = \frac{1}{9}

(a, b) = (0, - 4), r = \frac{1}{3}

Solution steps

x^{2} + (y + 4)^{2} = \frac{1}{9}

Rewrite

x^{2} + (y + 4)^{2} = \frac{1}{9}

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = (\frac{1}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = \frac{1}{3}

x^{2} + (y - 6)^{2} = 9

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

x^{2} - 2 x + 1 + y^{2} + y + \frac{1}{2} = \frac{11}{4}

x^{2} + 2 x + y^{2} - 2 y - 45 = 0

4 - (y - 4)^{2} = (x^{2} + 6 x + 9)

What is x^2+(y+4)^2= 1/9 ?
The solution to x^2+(y+4)^2= 1/9 is Circle with (a,b)=(0,-4),r= 1/3