What is 0.38^2=(x+1.7)^2+(y+0.5)^2 ?

The solution to 0.38^2=(x+1.7)^2+(y+0.5)^2 is Circle with (a,b)=(-1.7,-1/2),r=0.38

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

0.38^2=(x+1.7)^2+(y+0.5)^2

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

(a, b) = (- 1.7, - \frac{1}{2}), r = 0.38

Solution steps

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

Rewrite

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

in the form of the standard circle equation

(x - (- 1.7))^{2} + (y - (- \frac{1}{2}))^{2} = 0.3 8^{2}

Therefore the circle properties are:

(a, b) = (- 1.7, - \frac{1}{2}), r = 0.38

What is 0.38^2=(x+1.7)^2+(y+0.5)^2 ?
The solution to 0.38^2=(x+1.7)^2+(y+0.5)^2 is Circle with (a,b)=(-1.7,-1/2),r=0.38