What is [x-(-3)]^2+(y-1)^2=10^2 ?

The solution to [x-(-3)]^2+(y-1)^2=10^2 is Circle with (a,b)=(-3,1),r=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

[x-(-3)]^2+(y-1)^2=10^2

[x - (- 3)]^{2} + (y - 1)^{2} = 1 0^{2}

(a, b) = (- 3, 1), r = 10

Solution steps

(x - (- 3))^{2} + (y - 1)^{2} = 1 0^{2}

Rewrite

(x - (- 3))^{2} + (y - 1)^{2} = 1 0^{2}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 10

What is [x-(-3)]^2+(y-1)^2=10^2 ?
The solution to [x-(-3)]^2+(y-1)^2=10^2 is Circle with (a,b)=(-3,1),r=10