What is x^2+y^2-x-2y-1=0 ?

The solution to x^2+y^2-x-2y-1=0 is Circle with (a,b)=(1/2 ,1),r= 3/2

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x^2+y^2-x-2y-1=0

x^{2} + y^{2} - x - 2 y - 1 = 0

(a, b) = (\frac{1}{2}, 1), r = \frac{3}{2}

Solution steps

x^{2} + y^{2} - x - 2 y - 1 = 0

Rewrite

x^{2} + y^{2} - x - 2 y - 1 = 0

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 1)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 1), r = \frac{3}{2}

What is x^2+y^2-x-2y-1=0 ?
The solution to x^2+y^2-x-2y-1=0 is Circle with (a,b)=(1/2 ,1),r= 3/2