What is y-7=-1/16 (x-10)^2 ?

The solution to y-7=-1/16 (x-10)^2 is Parabola with (h,k)=(10,7),p=-4

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y-7=-1/16 (x-10)^2

y - 7 = - \frac{1}{16} (x - 10)^{2}

(h, k) = (10, 7), p = - 4

Solution steps

y - 7 = - \frac{1}{16} (x - 10)^{2}

Rewrite

y - 7 = - \frac{1}{16} (x - 10)^{2}

in the standard form:

4 (- 4) (y - 7) = (x - 10)^{2}

Therefore parabola properties are:

(h, k) = (10, 7), p = - 4

x^{2} = y - 1

x = y^{2} + 2 y - 1

2 x^{2} + 3 y + 14 = (x - 2)^{2}

x^{2} = 32 y

(y + 3)^{2} = 4 (x - 2)

What is y-7=-1/16 (x-10)^2 ?
The solution to y-7=-1/16 (x-10)^2 is Parabola with (h,k)=(10,7),p=-4