What is 2x^2+3y+14=(x-2)^2 ?

The solution to 2x^2+3y+14=(x-2)^2 is Parabola with (h,k)=(-2,-2),p=-3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+3y+14=(x-2)^2

2 x^{2} + 3 y + 14 = (x - 2)^{2}

(h, k) = (- 2, - 2), p = - \frac{3}{4}

Solution steps

2 x^{2} + 3 y + 14 = (x - 2)^{2}

Rewrite

2 x^{2} + 3 y + 14 = (x - 2)^{2}

in the standard form

4 (- \frac{3}{4}) (y - (- 2)) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 2), p = - \frac{3}{4}

x^{2} = 32 y

(y + 3)^{2} = 4 (x - 2)

y + 6 = 12 x^{2}

(x + 3) + (y - 2)^{2} = 0

y^{2} = \frac{1}{4} x

What is 2x^2+3y+14=(x-2)^2 ?
The solution to 2x^2+3y+14=(x-2)^2 is Parabola with (h,k)=(-2,-2),p=-3/4