x=y^2+2y-1

Lösung

x = y^{2} + 2 y - 1

(h, k) = (- 2, - 1), p = \frac{1}{4}

Schritte zur Lösung

x = y^{2} + 2 y - 1

Rewrite

x = y^{2} + 2 y - 1

in the standard form

4 \cdot \frac{1}{4} (x - (- 2)) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 1), p = \frac{1}{4}