What is (x-12)^2+(y+16)^2=400 ?

The solution to (x-12)^2+(y+16)^2=400 is Circle with (a,b)=(12,-16),r=20

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(x-12)^2+(y+16)^2=400

(x - 12)^{2} + (y + 16)^{2} = 400

(a, b) = (12, - 16), r = 20

Solution steps

(x - 12)^{2} + (y + 16)^{2} = 400

Rewrite

(x - 12)^{2} + (y + 16)^{2} = 400

in the form of the standard circle equation

(x - 12)^{2} + (y - (- 16))^{2} = 2 0^{2}

Therefore the circle properties are:

(a, b) = (12, - 16), r = 20

What is (x-12)^2+(y+16)^2=400 ?
The solution to (x-12)^2+(y+16)^2=400 is Circle with (a,b)=(12,-16),r=20