What is (x+7)^2+(y-2)^2=64 ?

The solution to (x+7)^2+(y-2)^2=64 is Circle with (a,b)=(-7,2),r=8

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(x+7)^2+(y-2)^2=64

(x + 7)^{2} + (y - 2)^{2} = 64

(a, b) = (- 7, 2), r = 8

Solution steps

(x + 7)^{2} + (y - 2)^{2} = 64

Rewrite

(x + 7)^{2} + (y - 2)^{2} = 64

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 2)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 7, 2), r = 8

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{4} = 1

x^{2} - 4 y + y^{2} - 21 = 0

(x - 2)^{(2)} + (y - 3)^{(2)} = 2^{(2)}

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

What is (x+7)^2+(y-2)^2=64 ?
The solution to (x+7)^2+(y-2)^2=64 is Circle with (a,b)=(-7,2),r=8