What is (x+1/2)^2+(y-4/5)^2= 9/4 ?

The solution to (x+1/2)^2+(y-4/5)^2= 9/4 is Circle with (a,b)=(-1/2 , 4/5),r= 3/2

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(x+1/2)^2+(y-4/5)^2= 9/4

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

(a, b) = (- \frac{1}{2}, \frac{4}{5}), r = \frac{3}{2}

Solution steps

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

Rewrite

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - \frac{4}{5})^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, \frac{4}{5}), r = \frac{3}{2}

x^{2} + 8 x + y^{2} - 2 y + 8 = 0

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x^{(2)} + y^{(2)} - 6 x - 8 y - 3 = 0

- 2 x^{2} - 36 x - 2 y^{2} - 122 = 0

x^{2} + y^{2} - x + 6 y = 1

What is (x+1/2)^2+(y-4/5)^2= 9/4 ?
The solution to (x+1/2)^2+(y-4/5)^2= 9/4 is Circle with (a,b)=(-1/2 , 4/5),r= 3/2