What is (x^2-10x)+(y^2+9y)=-1 ?

The solution to (x^2-10x)+(y^2+9y)=-1 is Circle with (a,b)=(5,-9/2),r=(sqrt(177))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2-10x)+(y^2+9y)=-1

(x^{2} - 10 x) + (y^{2} + 9 y) = - 1

(a, b) = (5, - \frac{9}{2}), r = \frac{177}{2}

Solution steps

x^{2} - 10 x + (y^{2} + 9 y) = - 1

Rewrite

x^{2} - 10 x + (y^{2} + 9 y) = - 1

in the form of the standard circle equation

(x - 5)^{2} + (y - (- \frac{9}{2}))^{2} = (\frac{177}{2})^{2}

Therefore the circle properties are:

(a, b) = (5, - \frac{9}{2}), r = \frac{177}{2}

x^{2} + y^{2} - 4 x + 2 y > 4

4 x - 8 y + 12 = x^{2} + y^{2}

y^{2} - 26 x + 25 y + 5 = - x^{2}

(x - 5)^{2} + (y - 22)^{2} = 10

y^{2} = - x^{2} + 1

What is (x^2-10x)+(y^2+9y)=-1 ?
The solution to (x^2-10x)+(y^2+9y)=-1 is Circle with (a,b)=(5,-9/2),r=(sqrt(177))/2