What is (x-sqrt(5))^2+(y-2sqrt(2))^2=10 ?

The solution to (x-sqrt(5))^2+(y-2sqrt(2))^2=10 is Circle with (a,b)=(sqrt(5),2sqrt(2)),r=sqrt(10)

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(x-sqrt(5))^2+(y-2sqrt(2))^2=10

(x - 5)^{2} + (y - 22)^{2} = 10

(a, b) = (5, 22), r = 10

Solution steps

(x - 5)^{2} + (y - 22)^{2} = 10

Rewrite

(x - 5)^{2} + (y - 22)^{2} = 10

in the form of the standard circle equation

(x - 5)^{2} + (y - 22)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (5, 22), r = 10

y^{2} = - x^{2} + 1

y^{2} = - x^{2} + 5

(x - 2)^{2} + y^{2} = 49

(x + 5)^{2} + (y + 1)^{2} = 9

(x - 3)^{2} + (y + 2)^{2} = 4^{2}

What is (x-sqrt(5))^2+(y-2sqrt(2))^2=10 ?
The solution to (x-sqrt(5))^2+(y-2sqrt(2))^2=10 is Circle with (a,b)=(sqrt(5),2sqrt(2)),r=sqrt(10)