What is 4x-8y+12=x^2+y^2 ?

The solution to 4x-8y+12=x^2+y^2 is Circle with (a,b)=(2,-4),r=4sqrt(2)

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4x-8y+12=x^2+y^2

4 x - 8 y + 12 = x^{2} + y^{2}

(a, b) = (2, - 4), r = 42

Solution steps

4 x - 8 y + 12 = x^{2} + y^{2}

Rewrite

4 x - 8 y + 12 = x^{2} + y^{2}

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 4))^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (2, - 4), r = 42

y^{2} - 26 x + 25 y + 5 = - x^{2}

(x - 5)^{2} + (y - 22)^{2} = 10

y^{2} = - x^{2} + 1

y^{2} = - x^{2} + 5

(x - 2)^{2} + y^{2} = 49

What is 4x-8y+12=x^2+y^2 ?
The solution to 4x-8y+12=x^2+y^2 is Circle with (a,b)=(2,-4),r=4sqrt(2)