What is x^2+y^2-6x+8y+21=0 ?

The solution to x^2+y^2-6x+8y+21=0 is Circle with (a,b)=(3,-4),r=2

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x^2+y^2-6x+8y+21=0

x^{2} + y^{2} - 6 x + 8 y + 21 = 0

(a, b) = (3, - 4), r = 2

Solution steps

x^{2} + y^{2} - 6 x + 8 y + 21 = 0

Rewrite

x^{2} + y^{2} - 6 x + 8 y + 21 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 4))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, - 4), r = 2

x^{(2)} + y^{(2)} + 4 x - 6 y - 3 = 0

x^{2} + y^{2} - 2 x - 4 y + 4 \leq 0

x^{2} + y^{2} + 6 x - 18 y + 25 = 0

5 = ((x + 1)^{2} + (y - (- 5))^{2})^{2}

x^{(2)} - 6 x + y^{(2)} + 4 y = 3

What is x^2+y^2-6x+8y+21=0 ?
The solution to x^2+y^2-6x+8y+21=0 is Circle with (a,b)=(3,-4),r=2