What is x^{(2)}+y^{(2)}+4x-6y-3=0 ?

The solution to x^{(2)}+y^{(2)}+4x-6y-3=0 is Circle with (a,b)=(-2,3),r=4

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x^{(2)}+y^{(2)}+4x-6y-3=0

x^{(2)} + y^{(2)} + 4 x - 6 y - 3 = 0

(a, b) = (- 2, 3), r = 4

Solution steps

x^{2} + y^{2} + 4 x - 6 y - 3 = 0

Rewrite

x^{2} + y^{2} + 4 x - 6 y - 3 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 4

x^{2} + y^{2} - 2 x - 4 y + 4 \leq 0

x^{2} + y^{2} + 6 x - 18 y + 25 = 0

5 = ((x + 1)^{2} + (y - (- 5))^{2})^{2}

x^{(2)} - 6 x + y^{(2)} + 4 y = 3

x^{2} + y^{2} - 6 x + 12 y + 20 = 0

What is x^{(2)}+y^{(2)}+4x-6y-3=0 ?
The solution to x^{(2)}+y^{(2)}+4x-6y-3=0 is Circle with (a,b)=(-2,3),r=4