What is x^2+y^2+6x-18y+25=0 ?

The solution to x^2+y^2+6x-18y+25=0 is Circle with (a,b)=(-3,9),r=sqrt(65)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+6x-18y+25=0

x^{2} + y^{2} + 6 x - 18 y + 25 = 0

(a, b) = (- 3, 9), r = 65

Solution steps

x^{2} + y^{2} + 6 x - 18 y + 25 = 0

Rewrite

x^{2} + y^{2} + 6 x - 18 y + 25 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 9)^{2} = (65)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 9), r = 65

5 = ((x + 1)^{2} + (y - (- 5))^{2})^{2}

x^{(2)} - 6 x + y^{(2)} + 4 y = 3

x^{2} + y^{2} - 6 x + 12 y + 20 = 0

x^{2} + 8 x + y^{2} - 2 y + 17 = 4 x^{2} - 24 x + 4 y^{2} - 16 y + 52

(x - 6)^{2} + (y - 3)^{2} = 324

What is x^2+y^2+6x-18y+25=0 ?
The solution to x^2+y^2+6x-18y+25=0 is Circle with (a,b)=(-3,9),r=sqrt(65)