What is x^2+y^2-8x+6y=11 ?

The solution to x^2+y^2-8x+6y=11 is Circle with (a,b)=(4,-3),r=6

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x^2+y^2-8x+6y=11

x^{2} + y^{2} - 8 x + 6 y = 11

(a, b) = (4, - 3), r = 6

Solution steps

x^{2} + y^{2} - 8 x + 6 y = 11

Rewrite

x^{2} + y^{2} - 8 x + 6 y = 11

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 3))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (4, - 3), r = 6

What is x^2+y^2-8x+6y=11 ?
The solution to x^2+y^2-8x+6y=11 is Circle with (a,b)=(4,-3),r=6