What is (x-1)^2+(y+5)^2=25 ?

The solution to (x-1)^2+(y+5)^2=25 is Circle with (a,b)=(1,-5),r=5

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(x-1)^2+(y+5)^2=25

(x - 1)^{2} + (y + 5)^{2} = 25

(a, b) = (1, - 5), r = 5

Solution steps

(x - 1)^{2} + (y + 5)^{2} = 25

Rewrite

(x - 1)^{2} + (y + 5)^{2} = 25

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 5))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (1, - 5), r = 5

x^{2} + y^{2} - \frac{12}{11} x - \frac{84}{11} y - \frac{640}{11} = 0

x^{2} + 8 x + y^{2} + 2 y + 13 = 0

x^{2} + y^{2} - 6 x + 4 y - 2 = 0

(x + \frac{5}{7})^{2} + (y + \frac{2}{7})^{2} = 8

x^{2} + y^{2} - 2 x + 4 y - 5 = 0

What is (x-1)^2+(y+5)^2=25 ?
The solution to (x-1)^2+(y+5)^2=25 is Circle with (a,b)=(1,-5),r=5