What is x^2+y^2-2x+4y-5=0 ?

The solution to x^2+y^2-2x+4y-5=0 is Circle with (a,b)=(1,-2),r=sqrt(10)

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x^2+y^2-2x+4y-5=0

x^{2} + y^{2} - 2 x + 4 y - 5 = 0

(a, b) = (1, - 2), r = 10

Solution steps

x^{2} + y^{2} - 2 x + 4 y - 5 = 0

Rewrite

x^{2} + y^{2} - 2 x + 4 y - 5 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 10

What is x^2+y^2-2x+4y-5=0 ?
The solution to x^2+y^2-2x+4y-5=0 is Circle with (a,b)=(1,-2),r=sqrt(10)