What is (x+2)^2+(y-3)^2=2 ?

The solution to (x+2)^2+(y-3)^2=2 is Circle with (a,b)=(-2,3),r=sqrt(2)

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(x+2)^2+(y-3)^2=2

(x + 2)^{2} + (y - 3)^{2} = 2

(a, b) = (- 2, 3), r = 2

Solution steps

(x + 2)^{2} + (y - 3)^{2} = 2

Rewrite

(x + 2)^{2} + (y - 3)^{2} = 2

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 2

What is (x+2)^2+(y-3)^2=2 ?
The solution to (x+2)^2+(y-3)^2=2 is Circle with (a,b)=(-2,3),r=sqrt(2)