What is 2x^2+2y^2=32 ?

The solution to 2x^2+2y^2=32 is Circle with (a,b)=(0,0),r=4

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2x^2+2y^2=32

2 x^{2} + 2 y^{2} = 32

(a, b) = (0, 0), r = 4

Solution steps

2 x^{2} + 2 y^{2} = 32

Rewrite

2 x^{2} + 2 y^{2} = 32

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 4

What is 2x^2+2y^2=32 ?
The solution to 2x^2+2y^2=32 is Circle with (a,b)=(0,0),r=4