What is 4x^2+4y^2-4x+2y=1 ?

The solution to 4x^2+4y^2-4x+2y=1 is Circle with (a,b)=(1/2 ,-1/4),r= 3/4

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4x^2+4y^2-4x+2y=1

4 x^{2} + 4 y^{2} - 4 x + 2 y = 1

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = \frac{3}{4}

Solution steps

4 x^{2} + 4 y^{2} - 4 x + 2 y = 1

Rewrite

4 x^{2} + 4 y^{2} - 4 x + 2 y = 1

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - (- \frac{1}{4}))^{2} = (\frac{3}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = \frac{3}{4}

What is 4x^2+4y^2-4x+2y=1 ?
The solution to 4x^2+4y^2-4x+2y=1 is Circle with (a,b)=(1/2 ,-1/4),r= 3/4