What is (x+4)^2+(y-2)^2=4 ?

The solution to (x+4)^2+(y-2)^2=4 is Circle with (a,b)=(-4,2),r=2

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(x+4)^2+(y-2)^2=4

(x + 4)^{2} + (y - 2)^{2} = 4

(a, b) = (- 4, 2), r = 2

Solution steps

(x + 4)^{2} + (y - 2)^{2} = 4

Rewrite

(x + 4)^{2} + (y - 2)^{2} = 4

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 2)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 4, 2), r = 2

x^{2} + y^{2} - 10 x - 24 y + 25 = 0

x^{2} - 2 x + 1 + y^{2} - 4 y + 4 = 196

(x - 3)^{2} + (Y (x) - (- 2))^{2} = (\frac{1}{2})^{2}

4 x^{2} + 4 y^{2} - 24 x + 4 y + 9 = 0

x^{2} + y^{2} - 8 x + 4 y + 19 = 0

What is (x+4)^2+(y-2)^2=4 ?
The solution to (x+4)^2+(y-2)^2=4 is Circle with (a,b)=(-4,2),r=2