What is (x^2}{16}+\frac{(y+1)^2)/4-1=0 ?

The solution to (x^2}{16}+\frac{(y+1)^2)/4-1=0 is Ellipse with (h,k)=(0,-1),a=4,b=2

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(x^2}{16}+\frac{(y+1)^2)/4-1=0

\frac{x ^{2}}{16} + \frac{( y + 1 ) ^{2}}{4} - 1 = 0

(h, k) = (0, - 1), a = 4, b = 2

Solution steps

\frac{x ^{2}}{16} + \frac{( y + 1 ) ^{2}}{4} - 1 = 0

Rewrite

\frac{x ^{2}}{16} + \frac{( y + 1 ) ^{2}}{4} - 1 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 1), a = 4, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, - 1), a = 4, b = 2

\frac{( x ^{2} )}{25} + \frac{( y ^{2} )}{9} = 1

x^{2} + (\frac{y + 3}{2})^{2} = 4

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

y^{2} - x - 4 y + 3 = 0

x = 2 y^{2} - 4

What is (x^2}{16}+\frac{(y+1)^2)/4-1=0 ?
The solution to (x^2}{16}+\frac{(y+1)^2)/4-1=0 is Ellipse with (h,k)=(0,-1),a=4,b=2