y^2-x-4y+3=0

Lösung

y^{2} - x - 4 y + 3 = 0

(h, k) = (- 1, 2), p = \frac{1}{4}

Schritte zur Lösung

y^{2} - x - 4 y + 3 = 0

Rewrite

y^{2} - x - 4 y + 3 = 0

in the standard form

4 \cdot \frac{1}{4} (x - (- 1)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 2), p = \frac{1}{4}

x = 2 y^{2} - 4

(y - 33)^{2} = 4 a (x - h)

y^{2} + 4 x - 8 y + 12 = 0

2 x - y^{2} = 10

x^{2} = - 10 y