What is 2x^2-3y^2=8 ?

The solution to 2x^2-3y^2=8 is Hyperbola with (h,k)=(0,0),a=2,b=(2sqrt(2))/(sqrt(3))

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2x^2-3y^2=8

2 x^{2} - 3 y^{2} = 8

(h, k) = (0, 0), a = 2, b = \frac{2 2}{3}

Solution steps

2 x^{2} - 3 y^{2} = 8

Rewrite

2 x^{2} - 3 y^{2} = 8

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{2 2}{3} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = \frac{2 2}{3}

\frac{( ( x - 6 ) ^{2} )}{( 1 )} - \frac{( ( y - 5 ) ^{2} )}{( 3 )} = 1

10 x^{2} + 7 y^{2} - 5 = 1

0.11 x^{2} + 0.25 y^{2} = 1

2 x^{2} + 3 y^{2} + 4 x = 1

3 x^{2} + 8 y^{2} + 12 x + 48 y + 60 = 0

What is 2x^2-3y^2=8 ?
The solution to 2x^2-3y^2=8 is Hyperbola with (h,k)=(0,0),a=2,b=(2sqrt(2))/(sqrt(3))