What is 3x^2+8y^2+12x+48y+60=0 ?

The solution to 3x^2+8y^2+12x+48y+60=0 is Ellipse with (h,k)=(-2,-3),a=2sqrt(2),b=sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2+8y^2+12x+48y+60=0

3 x^{2} + 8 y^{2} + 12 x + 48 y + 60 = 0

(h, k) = (- 2, - 3), a = 22, b = 3

Solution steps

3 x^{2} + 8 y^{2} + 12 x + 48 y + 60 = 0

Rewrite

3 x^{2} + 8 y^{2} + 12 x + 48 y + 60 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, - 3), a = 22, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 2, - 3), a = 22, b = 3

16 x^{2} + 25 y^{2} + 32 x - 384 = 0

9 x^{2} + 4 y^{2} - 36 x + 24 y - 1 = 0

x^{2} + 2 y^{2} = 1

y^{2} + 2 x^{2} - 2 y + 4 x - 6 = 0

x^{2} + 3 y^{2} - 6 x + 6 y = 0

What is 3x^2+8y^2+12x+48y+60=0 ?
The solution to 3x^2+8y^2+12x+48y+60=0 is Ellipse with (h,k)=(-2,-3),a=2sqrt(2),b=sqrt(3)