What is 2x^2-4y^2=16 ?

The solution to 2x^2-4y^2=16 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2

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2x^2-4y^2=16

2 x^{2} - 4 y^{2} = 16

(h, k) = (0, 0), a = 22, b = 2

Solution steps

2 x^{2} - 4 y^{2} = 16

Rewrite

2 x^{2} - 4 y^{2} = 16

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 22, b = 2

y^{2} - x^{2} = 3

x^{2} - y^{2} - 2 x - 8 = 0

4 x^{2} - 9 y^{2} - 36 < 0

2 x^{2} - 3 y^{2} = 8

\frac{( ( x - 6 ) ^{2} )}{( 1 )} - \frac{( ( y - 5 ) ^{2} )}{( 3 )} = 1

What is 2x^2-4y^2=16 ?
The solution to 2x^2-4y^2=16 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2