What is x^2+y^2=8(x+y)+4 ?

The solution to x^2+y^2=8(x+y)+4 is Circle with (a,b)=(4,4),r=6

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x^2+y^2=8(x+y)+4

x^{2} + y^{2} = 8 (x + y) + 4

(a, b) = (4, 4), r = 6

Solution steps

x^{2} + y^{2} = 8 (x + y) + 4

Rewrite

x^{2} + y^{2} = 8 (x + y) + 4

in the form of the standard circle equation

(x - 4)^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (4, 4), r = 6

x^{2} + y^{2} + 4 x - 12 y + 24 = 0

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

8 x + x^{2} - 2 y = 64 - y^{2}

(x - 3)^{2} = y - 2

(1) y = 2 x^{2}

What is x^2+y^2=8(x+y)+4 ?
The solution to x^2+y^2=8(x+y)+4 is Circle with (a,b)=(4,4),r=6