What is x^2+y^2+4x-12y+24=0 ?

The solution to x^2+y^2+4x-12y+24=0 is Circle with (a,b)=(-2,6),r=4

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x^2+y^2+4x-12y+24=0

x^{2} + y^{2} + 4 x - 12 y + 24 = 0

(a, b) = (- 2, 6), r = 4

Solution steps

x^{2} + y^{2} + 4 x - 12 y + 24 = 0

Rewrite

x^{2} + y^{2} + 4 x - 12 y + 24 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 6)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, 6), r = 4

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

8 x + x^{2} - 2 y = 64 - y^{2}

(x - 3)^{2} = y - 2

(1) y = 2 x^{2}

y^{2} = x - 1

What is x^2+y^2+4x-12y+24=0 ?
The solution to x^2+y^2+4x-12y+24=0 is Circle with (a,b)=(-2,6),r=4