What is x^2+y^2+2x+2y-2=0 ?

The solution to x^2+y^2+2x+2y-2=0 is Circle with (a,b)=(-1,-1),r=2

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x^2+y^2+2x+2y-2=0

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

(a, b) = (- 1, - 1), r = 2

Solution steps

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

Rewrite

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 1))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 1), r = 2

8 x + x^{2} - 2 y = 64 - y^{2}

(x - 3)^{2} = y - 2

(1) y = 2 x^{2}

y^{2} = x - 1

x + 4 y^{2} - 8 = 0

What is x^2+y^2+2x+2y-2=0 ?
The solution to x^2+y^2+2x+2y-2=0 is Circle with (a,b)=(-1,-1),r=2